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TLV703: Understand TLV703 output voltage accuracy!

Part Number: TLV703

if the typical output voltage accuracy value 0.5% is guaranteed at room temperature with factory test?

  • No. Typical values are not guarantees.

    Please note that the power dissipation inside the device will heat it up, so even if a guaranteed 25 °C value existed, it would be pretty much pointless.
  • Hi Clemens:

    Thanks for your reply.

    The load and input condition has been defined in the table as 10mA and Vin=Vout+2V. So the temperature rise will be small due to the loss in this conditoin. (0.01A*2V*254.1degree/W = 5 degree)

    In the datasheet, it say the typical value is 0.5% at room temperature, and the worst case is 2% with –40°C ≤ TJ ≤ 125°C. If you look at typical temperature varation in figure 5 is not anywhere near 1.5%. This make the typical curve in figure 5 pointless or the basic accuracy 0.5% is pointless. Am I wrong somewhere?

    BRs
  • In the worst case, both the initial accuracy and the temperature variation might be worse than the typical values shown in the graphs.
  • Thanks again for reply.

    0.5% typical is really not useful at all then. Don't understand why it is mentioned in the datasheet at the first place anyway. A distribution graphic with different batch woudl be helpfull.
  • Hi,

    Clemens is correct, the output accuracy is guaranteed max/min of +-2%, not the typical 0.5%. The initial accuracy and output variation over temperature for a given unit will vary but are guaranteed to be within +-2%. However, typical specs and characteristic graphs are measured and averaged in a bench setting, so they are useful in providing an idea of the general performance of the device.

    Figure 5 shows the output variation over temperature for a typical unit. The output rises by about one-fifth of a division to a maximum of 1.804 V over the recommended operating temperature. This corresponds to an output accuracy of (1.804 V - 1.8 V)/1.8 V * 100 = 0.22%, which is close to the typical accuracy spec.

    Thanks,
    Gerard
  • Thanks Gerard for the explanation.