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Tool/software: WEBENCH® Design Tools
first is the current the current in the coil
second the copper thickness reduction seems to increase the currant is this correct , the dc resistance increases and the currant increases.
can you please explain why
thanks Sean
Hi Sean,
The current depends on the resonant impedance of the LC tank (impedance at the resonant frequency) Irms = Vrms / Zresonance. So as the series resistance of the coil increases (with copper thickness reduction), due to increased damping, the resonant impedance actually decreases and hence the current through the LC tank increases (for a fixed rms input voltage). For example with LDC0851 and default coil selection, we get Resonance Impedance = 14408.49 Ohm. If we assume Vp-p of the LC driver = 3.3V (max supply voltage), Vrms = Vp-p/(2*sqrt(2) ) = 1.167V, so Irms = Vrms/Zresonance = 1.167/14408.49 = 0.08mA (same as you see in the tool).
To illustrate the resonant impedance variation with series resistance, below example shows the plot of impedance of parallel LC tank with varying series resistance of the Inductor (L = 5.35uH, C = 68pF, R = 4.54 Ohm, 5.46 Ohm, 7.7 Ohm). You can observe, as resistance increases the resonant impedance decreases. (Note: This is just an ideal example which shows the effect of damping on resonant impedance - the values may not match exactly with the coil designer tool as this example not include additional parasitic effects like self resonance of coil).
Regards,
Srikanth Pam
Online Design Tools