Hello,
I am running UART program in "CC2541_43_44_45_Peripherals_Software_Examples".
I set 14.4 kbps with
#define UART_BAUD_M 216
#define UART_BAUD_E 8
and didn't change default parameters as follows.
// Initialise bitrate = 14.4 kbps.
U0BAUD = UART_BAUD_M;
U0GCR = (U0GCR & ~U0GCR_BAUD_E) | UART_BAUD_E;
// Initialise UART protocol (start/stop bit, data bits, parity, etc.):
// USART mode = UART (U0CSR.MODE = 1)
U0CSR |= U0CSR_MODE;
// Start bit level = low => Idle level = high (U0UCR.START = 0).
U0UCR &= ~U0UCR_START;
// Stop bit level = high (U0UCR.STOP = 1).
U0UCR |= U0UCR_STOP;
// Number of stop bits = 1 (U0UCR.SPB = 0).
U0UCR &= ~U0UCR_SPB;
// Parity = disabled (U0UCR.PARITY = 0).
U0UCR &= ~U0UCR_PARITY;
// 9-bit data enable = 8 bits transfer (U0UCR.BIT9 = 0).
U0UCR &= ~U0UCR_BIT9;
// Level of bit 9 = 0 (U0UCR.D9 = 0), used when U0UCR.BIT9 = 1.
// Level of bit 9 = 1 (U0UCR.D9 = 1), used when U0UCR.BIT9 = 1.
// Parity = Even (U0UCR.D9 = 0), used when U0UCR.PARITY = 1.
// Parity = Odd (U0UCR.D9 = 1), used when U0UCR.PARITY = 1.
U0UCR &= ~U0UCR_D9;
// Flow control = disabled (U0UCR.FLOW = 0).
U0UCR &= ~U0UCR_FLOW;
// Bit order = LSB first (U0GCR.ORDER = 0).
U0GCR &= ~U0GCR_ORDER;
When I set my terminal as follows,
14.4kbps, Data bits = 8, Parity=none, Stop bits = 1, Handshanking = nong
I am supposed get this message
"Texas Instruments LPRF!"
But I got this,
"뷢H믢???E%jr$??e쀳<0>"
I can't guess what is wrong.
Could you advice please?
Best Regards,
YS
