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The gain difference is that for non-inverting, Cf can only lower gain towards 1V/V; while for inverting Cf can reduce gain towards 0V/V. I still confused why non-inverting,Cf can only lower gain towards 1V/V and inverting Cf can reduce gain towards 0V/V this part could you explain in detail please
The explanation for that statement is that at high frequencies the capacitor can be considered a short. In the case of non-inverting configuration, if the capacitor is a short the op amp is in a buffer configuration, which has a gain of 1V/V. If the capacitor is a short in the inverting configuration, it bypasses the opamp in the signal path, thus giving a gain of 0V/V.
With a perfect op amp the forward gain curve will continuously falls with frequency. The gain of a real op amp drops with higher frequency so it can not produce an ideal response.
Your mean is 20log(0V/V) is falling? but at high frequency there is a zero and pole right? I still don't understand this part I agree you said real op amp drop with higher frequency but how to explain 20log(0V/V)
