This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

PCM1865: 10uF input capacitor removal

Part Number: PCM1865
Other Parts Discussed in Thread: OPA1637,

I have a PCM1865 with a differential input from a OPA1637, I've heard that if the Vref (from PCM) is connected to the VCOM (of the OPA) I can remove the 10uF capacitors on the input reducing the manofacturing cost. How true is this? any drawbacks? Would you advice doing it?

  • Hi Ignacio,

    I believe this advice is coming from the first paragraph in Section 9.1.3 of the OPA1637 datasheet. The idea here is that the analog input pins of the ADC require some bias, typically half the supply voltage. By setting the common mode of the amplifier to be AVDD/2, you set the output of the op amp to exactly match the required bias. This would allow the design to remove the coupling caps since theoretically they are coupled to the same voltage already.

    That's the idea on paper at least. The OPA datasheet uses this advice in general for "precision ADCs" which this device used to belong to. However the PCM1865 datasheet specifically says to leave the coupling caps in place because the device self biases these pins to AVDD/2 on page 28. If there was any mismatch between the bias voltage and the op amp common mode, you would get a DC current that could impact the result of the ADC.

    On paper this idea sounds fine, but since the datasheet argues against it, I wouldn't recommend it as a solution.

    Best regards,
    Jeff McPherson

  • First of all thank you for the quick and accurate response. I have a follow up question, you mention AVDD/2, do I need to divide Vref by 2 and then conect to the VCOM? or thats done internally? maybe im missunderstanding.

  • Hi Ignacio,

    I see your second post, and the answer is the same, so I'll answer on your other post.