This thread has been locked.
If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.
Hi team:
As check with the D/S via TI.com. it did mentioned about the Tj spec, but i found the answer via e2e as below reply: Max recommended Tj for the DP83826 is 110°C for the E version and 90°C for the I version.
But there are something want to double confirm is that the ambient temperature of I version can reach 85 degrees Celsius. Why is the T junction temperature only so low as 90 degrees Celsius? According to the thermal resistance of 52°C/W and the power consumption of 45mA & 0.148W, at an ambient temperature of 85°C, the junction temperature has exceeded 90°C, which is inconsistent with the specification that it can be used at an ambient temperature of 85°C.
Your comments will be very appreciate.
BTW, why the DP83826E and I version have such a big temperature difference? DIE reason or design margin?
Hello,
Thank you for your query. We are checking with the internal teams on this, but as there is holiday, please expect delays in response. I will look to update at latest EoD 11/2.
Sincerely,
Gerome
Hi Allen,
After checking with the team, there are wide amounts of literature regarding thermal resistance calculations. The most relevant to you:
- Theta_J_A is used to compare between devices, but not for actual temperature calculations
- PSI_J_T is used for application calculations, using formula Tj = Tc + PSI_J_T * Sigma_Power. Tc is the temperature of the case top where customer would physically measure using a thermocouple.
Sincerely,
Gerome
Hi Gerome:
tks for the comments, but as i check, when we work at 85C°, using formula Tj = Tc + PSI_J_C * Sigma_Power = 85 + 42 *(3.3V*0.045mA)=85+6.237=91.237 > 90°C for the I version.
Does it exceed the specification requirements?
My apologies Allen, it was not PSI_J_C, but PSI_J_T. I have corrected my previous post to correct this typo. This would add .14C above the case temperature.
Sincerely,
Gerome
Noted,
so Tj = Tc + YJT * Sigma_Power = 85 + 2.1 *(3.3V*0.045mA)=85+0.311=85.311, am i correct?
but weird is that how the .14C comes?
add .14C above the case temperature.
Hi Allen,
The .14C comes from a total power contribution of 67mA maximum between VDDA/VDDIO at 3.3V. This would be added onto the measured temperature of the top of the IC from using a thermocouple.
Sincerely,
Gerome