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Tool/software:
We are using the DS125DF111 XFI retimer in our current project. We are having some difficulty programming the retimer.
Could you please help review the sequence below and let us know if we are missing anything?
This is what we are writing to the register space:
Register |
Value |
R/W |
Reason |
0xFF |
0x0C |
W |
Broadcast to all channel |
0x0A[3:2] |
0x1C |
W |
CDR reset override |
W |
Enable CDR reset override |
||
0x60 |
0x00 |
W |
VCO frequency settings |
0x61 |
0xB2 |
W |
|
0x62 |
0x90 |
W |
|
0x63 |
0xB3 |
W |
|
0x64 |
0xCD |
W |
|
0x0A[3:2] |
0x1 |
W |
Release CDR reset |
Do we need to write back to 0xFF register space anything at the end to get the retimer to lock to the input?
Hi Abeed,
Your register write sequence generally looks good and I don't see any major issues. I do have a few comments.
You do not need to write back to register 0xFF at the end of your sequence.
Best,
Lucas
Hi Lucas,
I have used this part in my previous design and the schematic and layout implementation is the same. I lost my previous correspondences from a few years ago regarding the programming sequence of these retimers.
We are looking at our SoC and ethernet switch side of things right now to make sure we are ok on that front. But as of now ethernet link is not yet up. Hence, this post is to reconfirm whether the sequence is correct and nothing out of the ordinary.
Responses to your questions in-line below...
Question: Do we need to write sequentially to bits 2 and 3 at register 0x0A to enable override and do CDR reset? Or is it OK to write at once 0x1C to 0x0A?
Thanks,
Abeed
Hi Abeed,
I understand, thank you for sharing a bit more background on your project. Given your answers, I don't see any issue with your register write sequence.
To answer your questions, yes there are status registers which indicate signal detect and CDR lock.
Please let me know what values you see in these registers.
Question: Do we need to write sequentially to bits 2 and 3 at register 0x0A to enable override and do CDR reset? Or is it OK to write at once 0x1C to 0x0A?
It is ok to assert both bits at the same time by simply writing 0x0A=0x1C.
Best,
Lucas