G2101 operates weird without emulator being connected.

Thanks for the quick response.  I can confirm that Vcc is stable and I do have 47k  from RST to Vcc and a 2n2 capacitor from RST to GND. I double check the HW and pretty sure that there is no issues.

I am using GRACE for configuring. However, I tried to built that project without any extra tools. The behavior is the same.

Here is my code:

	WDTCTL = WDTPW + WDTHOLD;               // Stop WDT

	//1Mhz
	if (CALBC1_1MHZ==0xFF)					// If calibration constants erased
	{
	     while(1);                          // do not load, trap CPU!!
	}
	DCOCTL = 0;                             // Select lowest DCOx and MODx settings
	BCSCTL1 = CALBC1_1MHZ;                  // Set range
	DCOCTL = CALDCO_1MHZ;                   // Set DCO step + modulation */

	/* Port 1 Output Register */
	P1OUT = 0;
	/* Port 1 Direction Register */
	P1DIR = BIT0 | BIT1 | BIT2 | BIT3 | BIT4 | BIT7;
	/* Port 1 Interrupt Edge Select Register */
	P1IES = 0;
	/* Port 1 Interrupt Flag Register */
	P1IFG = 0;
	/* Port 2 Output Register */
	P2OUT = 0;
	/* Port 2 Port Select Register */
	P2SEL &= ~(BIT6 | BIT7);
	/* Port 2 Direction Register */
	P2DIR = 0;
	/* Port 2 Interrupt Edge Select Register */
	P2IES = 0;
	/* Port 2 Interrupt Flag Register */
	P2IFG = 0;

	// TIMER
	CCTL0 = CCIE;                           // CCR0 interrupt enabled
	TACCR0 = 6249;
	TACTL = TASSEL_2 | ID_3 | MC_1;

        TACTL |= MC_1;						// Start 5mS timer

        __bis_SR_register(GIE);     			// General interrupt enable

I have only one interrupt enable which is from Timer A0:

// Timer A0 interrupt service routine
#if defined(__TI_COMPILER_VERSION__) || defined(__IAR_SYSTEMS_ICC__)
#pragma vector=TIMERA0_VECTOR
__interrupt void Timer_A (void)
#elif defined(__GNUC__)
void __attribute__ ((interrupt(TIMERA0_VECTOR))) Timer_A (void)
#else
#error Compiler not supported!
#endif
{
/*

*/

}

Thank you.

Hi Dennis,

Thanks for your help. The simplest way I can demonstrate the problem is this. P1.6 is input with no pull up/down resistor. I shorted it to GND. After initialization micro should turn P1.2 in HIGH. However, P1.0 always goes HIGH instead.

#include <msp430.h> 


void main(void)
{
	WDTCTL = WDTPW + WDTHOLD;               // Stop WDT

	//1Mhz
	if (CALBC1_1MHZ==0xFF)					// If calibration constants erased
	{
	     while(1);                          // do not load, trap CPU!!
	}
	DCOCTL = 0;                             // Select lowest DCOx and MODx settings
	BCSCTL1 = CALBC1_1MHZ;                  // Set range
	DCOCTL = CALDCO_1MHZ;                   // Set DCO step + modulation */

	/* Port 1 Output Register */
	P1OUT = 0;
	/* Port 1 Direction Register */
	P1DIR = BIT0 | BIT1 | BIT2 | BIT3 | BIT4 | BIT7;
	/* Port 1 Interrupt Edge Select Register */
	P1IES = 0;
	/* Port 1 Interrupt Flag Register */
	P1IFG = 0;
	/* Port 2 Output Register */
	P2OUT = 0;
	/* Port 2 Port Select Register */
	P2SEL &= ~(BIT6 | BIT7);
	/* Port 2 Direction Register */
	P2DIR = 0;
	/* Port 2 Interrupt Edge Select Register */
	P2IES = 0;
	/* Port 2 Interrupt Flag Register */
	P2IFG = 0;

	if (!(P1IN & BIT6)) // if P1.6 is LOW
		P1OUT |= BIT2;
	else
		P1OUT |= BIT0;

  	while(1);

}

Cheers,

Stan 

Any ideas why it goes a wrong way?

Does the code work OK on Launchpad with all jumpers except Vcc removed?

Sometimes reset does not work unless you exit debug-mode correctly by first pause button then stop button.

I guess there is something not right with you external board, schematic and gerbers will help.

Hi Tony,

I assembled this scheme on a prototype board and pretty sure that it is not HW issue.

I have a launchpad with G2452 will check this code there. In terms of the exit of debug mode will check it too.

Thank you

No matter how I exit debug mode custom board always works wrong. Launchpad with G2452 works well, no questions.

Stan,

you will not get releiable values when doing this

if( !(P1IN & BIT6) ) // if P1.6 is LOW
  P1OUT |= BIT2;
else
  P1OUT |= BIT0;

without having a pull-up/down-resistor connected to the input pin. Don't leave the pin floating. It will change it's value randomly. With a set jumper the potential is defined to 0, but without it, both statements could be true (only one at a time of course).

Dennis