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Original question:
Tool/software: Code Composer Studio
Dear team,
Customers have tested SD24_B and found problems when using it.
When the input voltage is 0, the result register still has a value, the 100nf capacitor has been connected, the code is modified on the official routine, the code is as follows.
The customer uses channel 5. In order to eliminate interference, both the positive and negative terminals are connected to DGND, but there are still very large values, and the value in the SD24BMEML5 register has been changing。
#include <msp430.h>
/* Unsigned integer to store SD24_B conversion result */
unsigned long results;
void main(void)
{
WDTCTL = WDTPW | WDTHOLD; // Stop WDT
SD24BCTL0 = SD24REFS | SD24SSEL_1; // Select internal REF
// Select SMCLK as SD24_B clock source
SD24BCCTL5 |= SD24SNGL; // Single conversion
SD24BINCTL5 |= SD24INTDLY0; // Interrupt on 3rd sample
SD24BIE |= SD24IE5; // Enable channel 2 interrupt
__delay_cycles(0x3600); // Delay for 1.5V REF startup
while (1)
{
SD24BCCTL5 |= SD24SC; // Set bit to start conversion
__bis_SR_register(LPM0_bits | GIE); // Enter LPM0 w/ interrupts
__no_operation();
__no_operation(); // SET BREAKPOINT HERE
}
}
#if defined(__TI_COMPILER_VERSION__) || defined(__IAR_SYSTEMS_ICC__)
#pragma vector=SD24B_VECTOR
__interrupt void SD24BISR(void)
#elif defined(__GNUC__)
void __attribute__ ((interrupt(SD24B_VECTOR))) SD24BISR (void)
#else
#error Compiler not supported!
#endif
{
switch (SD24BIV)
{
case SD24BIV_SD24OVIFG: // SD24MEM Overflow
break;
case SD24BIV_SD24TRGIFG: // SD24 Trigger IFG
break;
case SD24BIV_SD24IFG0: // SD24MEM0 IFG
break;
case SD24BIV_SD24IFG1: // SD24MEM1 IFG
break;
case SD24BIV_SD24IFG5: // SD24MEM2 IFG
results = SD24BMEMH5; // Save CH2 results (clears IFG)
results = (results << 16) | SD24BMEML5; // Concatenate lower and upper words
break;
default:break;
}
__bic_SR_register_on_exit(LPM0_bits); // Exit LPM0
}The link on E2EChina is 
Please help.
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