This thread has been locked.

If you have a related question, please click the "Ask a related question" button in the top right corner. The newly created question will be automatically linked to this question.

LM2705: supply two parallel LED strings

Part Number: LM2705

Hello Team, 

my customer wants to use LM2705MF in his display application as a backlight driver. They use the driver already in another application:

Since I'm unclear about the functionally of the controller I would like to know if we can use it in the following configuration:

The LED line is divided into 2 x 3 LEDs in series in parallel and the max current on both strings will be 40mA. This means that the 3 LEDs (6LEDs) are part of the control loop. How is the resistance, which is given here with 82 ohms, calculated or how do you get the 82 ohms? What current does this set up? And how does the control with the PWM via the shut down pin work? In addition, we would like to operate the controller with 5V at the entrance, which according to the data sheet should not be a problem. Why in this application, the voltage range is limited to 4.2V? Would be great if you could also provide a small description of how the IC works. As I said, I am not quite clear about the operating principle for this application.

Thank you 

Jan