LM76005-Q1: LM76005 junction temperature calculation method

hi:

    Is there a junction temperature calculation table for LM76005-Q1? Tj exceeds the standard seriously according to the following calculation method

According to the calculation method in Page 36 of the Specification, based on R θ JA,

If the inductance DCR=0.05 ohms and the ambient temperature is 85 ° C,

Then input VIN=36V, output 14V/3.5A, output power Pout=14 * 3.5=49w,

If the efficiency is 92%, the input power is Pin=49W/0.92=53.26W,

So the overall power loss is Ploss=53.26-49=4.26W

The loss of inductance is: PLloss=3.5A * 3.5A * 0.05 Ω=0.8575W

So the power loss on the IC is PIClose=Ploss - 1.1 * PLlose=4.26-0.9432=3.316W

If the ambient temperature is 85 ° C and the IC thermal resistance R θ JA is 29.6 ° C/W, the junction temperature on the IC Tj=85+3.316 * 29.6=183.15 ° C

TJMAX has seriously exceeded LM76005-Q1=150 ° C;