I use the load switch as a current limiter only (275mA) and don't actually need to be able to switch off the output. However, I have to ensure the lowest possible current consumption, which is why I still want to switch off the output in certain operating states via the EN pin (the ISE = 75µA supply current would be too high).
I am therefore interested in how high the leakage current is when the load switch is switched off, even if there is still voltage at the output via another circuit path (but with higher impedance): VIN = 3V, EN = 0V, VOUT <= 3V
If I have understood correctly from other posts, reverse current blocking is realized via two P-channel FETs connected against each other. With VOUT <= VIN, the leakage current of the protection diodes in the FETs should not play a role. Are there possibly other circuits/paths in the load switch that can lead to a reverse leakage current at the output? If yes, how much would that be (typically and worst case)?
Thanks!
