Hi all
I see the referensc circuit (Figure 1) of LM5005.
You selected the R7 resistance is 10Ω/1W.
However my customer can not prepare same spec resistance.
So my customer would like to use R7 10Ω / 1/4W spec resistance.
Is it OK?
Best Regards,
Sho
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Hi all
I see the referensc circuit (Figure 1) of LM5005.
You selected the R7 resistance is 10Ω/1W.
However my customer can not prepare same spec resistance.
So my customer would like to use R7 10Ω / 1/4W spec resistance.
Is it OK?
Best Regards,
Sho
The power dissipated in that resistor is
P=2⋅((1/2)⋅C ⋅V^2)⋅f
For C = 330 pF, f = 300 kHz and V = 75 V, I calculate P = 0.557 W. You will need more than 1/4 W resistor if you intend to operate up to 75 V input.