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TPS61099: Maximum value of R2

Part Number: TPS61099

Hi support team,
I have a question about the following sentence in the TPS61099 data-sheet.

9.2.1.1.2 Programming the Output Voltage, Page-16, SLVSD88K
"For the best accuracy, the current following through R2 should be 100 times larger than FB pin leakage current."

IFB_LKG is 10nA for TYP and 50nA for MAX.

Should the R2 current be above the MAX standard of 5uA?
Or is it okay to have a TYP standard of 1uA or higher?

I want to know the maximum value of R2.

R2 < VREF/(IFB_LKG*100) = 1V/5uA = 200kΩ ?

R2 < VREF/(IFB_LKG*100) = 1V/1uA = 1MΩ ?

Regards,
Dice-K