Hi Team,
I referred below link for using LDC LUT header file,
for that I referred multi_cam_codec_ldc_module application logic at [ti-processor-sdk-rtos-j784s4-evm-09_02_00_05/vision_apps/apps/basic_demos/app_multi_cam_codec/multi_cam_codec_ldc_module.c] path
where they are using ldc_lut_1920x1080.h for lut and we want to use same logic
Step1: We used the Matlab script and get the x,y co-ordinate values. As follow:
Step2: then pass this mesh.txt file to DCC tool:
And generate then XML and LUT.txt file:
Step3: XML and LUT.txt file copied in wdr folder.
Step4: updated generate_dcc.sh file updated the XML name:
Step5: after building imaging folder dcc_ldc_ar023_wdr.h file is generated in include folder
This file we are giving as mesh_img input in code.
But for our file the formula calculation is as follows:
ldcObj->table_width = (((ldcObj->image_width / (1 << ldcObj->ds_factor)) + 1u) + 15u) & (~15u);
ldcObj->table_height = (ldcObj->image_height / (1 << ldcObj->ds_factor)) + 1u;
ldcObj->table_width = 1920/4 +16= 496
ldcObj->table_height = 1280/4 +1 = 321
Total size of the table = 496*321 = 159216
And have unint 32 i.e. multiplied with 4 bytes
Then
Mesh_img = 159216 * 4 = 636864 which is not matching 623812 with dcc_ldc_ar023_wdr.h data size:
Question is
1. How can we calculate the mesh_img size formula to get same bytes in dcc_ldc_ar023_wdr.h file ?, we are getting garbage values
