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Hi team,
There is a description on page 17 of FDC2212 datasheet:”The reference count value must be chosen to support the required number of effective bits (ENOB). For example, if an ENOB of 13 bits is required, then a minimum conversion time of 213 = 8192 clock cycles is required.”
I don't understand why the relationship between ENOB and conversion time is like this. Can anyone help me understand it?
Thanks
Amy Luo
Hi,
You can think of the reference count as the sampling rate. The sampling time can be set by the reference count, RCOUNT_CHx. The RCOUNT value multiplied by 16 is the number of reference clock cycles, which will determine the ENOB. Please check out the text above Table 6 in the datasheet.
Regards
Sharath.