Compiler: CCS Compile data type

YCH

Prodigy 50 points

Tool/software: TI C/C++ Compiler

Q1:Compile data type No uint8,How to use CLA?

Q2:Uint8, uint16, global variable in the map data size is consistent。

look at variable CCPTEST1,CCPTEST2,CCPTEST3.

CCPTEST1 is Uint32.CCPTEST2 is unsiged char ,CCPTEST3 is Uint16.

Then in the map file,CCPTEST3 and CCPTEST2 has same size.(0000a9c4 - 0000a9c3 = 1),(0000a9c3 - 0000a9c2 = 1).

Q3：ccs map file ，What is the length of an address unit, 8byte or 16byte? as that，(0000a9c4 - 0000a9c3 = 1) ，what the size of the 1？

over 5 years ago

0 George Mock over 5 years ago

TI__Guru**** 235775 points

On both the C28x CPU and the CLA, the smallest addressable unit of memory is a 16-bit word. Among other things, this means the type char is 16-bits wide. Throughout the entire toolchain, including the linker map file, each memory address location corresponds to a 16-bit word.

The article Byte Accesses with the C28x CPU is generally useful.

Thanks and regards,

-George

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Compiler: CCS Compile data type