**Part Number:**CC1120

**Other Parts Discussed in Thread:**CC1121

Looking for clarity & finality on this subject...

I have seen (5) different iterations on Carlson's Rule for calculating transmitter bandwidth each producing (5) different results.

If dealing with a simple 2-level FSK signal and a simple bit rate, can the formula be simplified or reduced to:

Bandwidth = BPS + Separation

where BPS is 2 x the Modulation Frequency and Separation is 2 x the Frequency Deviation.

So, for a BPS of 4.8KHz and a Separation of 20K, the Bandwidth is 24.8KHz?

(The period of 4.8KBPS being actually 2.4KHz and the Separation being actually the total +/- offset from the CW center frequency.)

Part of the ambiguity that I have seen is Deviation is not always qualified as being strictly a (+/-) figure but sometimes is actually total Deviation (aka Separation).

Thanks,

--

Jay Zebryk