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I want Design a circuit for over current and short circuit protection,and also want
input voltage ~= output voltage
i have 24V/10A input power supply , i want its divided in ten parts as figure.
Kindly suggest me what i do for it.
I would recommend 2 x TPS4H160 and one TPS2H160. The on resistance upper limit is 280mOhm at 150C junction temperature. That makes the max voltage drop of 280mV between the 24V supply and the load. The device max power dissipation 4 x 0.28W = 1.12W. The junction temperature rise above ambient is 1.12W x 32.7C/W = 36.6C.
At 1 A load current the current limit accuracy is15% max and the device is fully protected and has full diagnostic features.
To find the latest information on power Switches, visit www.ti.com/powerswitch
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In reply to Mahmoud Harmouch:
can you provide me circuit diagram ? plz.
In reply to sudesh verma:
Sure will do. I understood the design requires over current protection but I also need to know if the high side switch should communicate with MCU to report the faults on any single channel.
i'm not use any MCU or any External Power Supply.i want apply fixed Input Voltage (1~7)V on Inputs Pins.
please check the attached circuit diagram and let me know for further assistance.
how to calculate value of resistance? Kcl=?
Please refer to datasheet page 16. The formula relating external limiting resistor RcL, load current IOUT and current ratio KcL: RcL = VcL(th) x KcL/IOUT.
The highest variation is from current ratio KcL and KcL = KcL(typ) x (1 + dKcL/KcL(typ)). dKcL/KcL(typ) is the accuracy and it is +/-15% at 1A load current.
For making sure the load current does not hit the current limit during normal operation, RcL should be calculated with the lowest current ratio accuracy.
That means RcL = VcL(th) x KcL(typ) x (1 + dKcL/KcL(typ))/IOUT.
At 1A load current, RcL = 0.8V x 2500 x (1 - 0.15)/1A = 1700 Ohms
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