How to convert phase noise unit "dBc/Hz" to "rad/√Hz" ?

Hello,
I can help with going from dBc/Hz to rad or seconds.

Say you have -150dB/Hz of phase noise. The 1st thing to do is to convert this to total integrated noise. I will assume the noise is flat across frequency and the clock frequency is 50 MHz. Also, assume an integration noise BW of 2*50 MHz = 100 MHz. In that case the total integrated noise is PN_dBc = -150 dBc + (10*Log(100 MHz)) = -150dBc + 80 = -70 dBc.

To then get the rms phase noise in radians = SQRT[2*{10^(PN_dBc/10)}] = 4.47*10^(-4)

At this point if you wanted rad/Hz, you would simply divide the number above by the clock frequency, so 4.47*10^(-4)/50 MHz =8.94*10^(-12)

Now if you want the jitter in seconds which is fairly common, divide the number above by 2*pi, to get a jitter of 1.423 ps.

Hope this helps.
-Samir