TI E2E support forums
TI E2E support forums
  • User
  • Site
  • Search
  • User
  • E2E™ design support >
  • Forums
    • Amplifiers
    • API solutions
    • Audio
    • Clock & timing
    • Data converters
    • DLP® products
    • Interface
    • Isolation
    • Logic
    • Microcontrollers
    • Motor drivers
    • Power management
    • Processors
    • RF & microwave
    • Sensors
    • Site support
    • Switches & multiplexers
    • Tools
    • Wireless connectivity
    • Archived forums
    • Archived groups
  • Technical articles
  • TI training
    • Tech days
    • Online training
    • Live events
    • Power Supply Design Seminar
  • Getting started
  • 简体中文
  • More
  • Cancel


Search tips
Showing 3 results View by: Thread Post Sort by
  • DS90LV028AH High Temperature 3V LVDS Dual Differential Line Receiver

    Ken Elmer
    Ken Elmer
    Other Parts Discussed in Thread: DS90LV028AH I have a question regarding Texas Instruments DS90LV028AH High Temperature 3V LVDS Dual Differential Line Receiver. A 100 ohm input termination resistor is recommended in the specification. What are the effects…
    • over 10 years ago
    • Interface
    • Interface forum
  • DS90LV012A: Without LINE Termination

    Brian Wang0928
    Brian Wang0928
    TI Thinks Resolved
    Part Number: DS90LV012A Other Parts Discussed in Thread: DS90LV028AH , SN65MLVD204B , DS90LV049H , DS90LV028AQ-Q1 , DS90LV049Q-Q1 Is there similar product to DS90LV012A without LINE termination of 100 Ohm and TA is up to 125degree? Thanks. Regards…
    • over 3 years ago
    • Interface
    • Interface forum
  • RE: C6678 Performance Discrepancy Between "Benchmarks" and EVM Board

    Ken Elmer
    Ken Elmer
    I do not have a suggestion for you. Perhaps you can answer a question I have. I have a question regarding Texas Instruments DS90LV028AH High Temperature 3V LVDS Dual Differential Line Receiver. A 100 ohm input termination resistor is recommended in the…
    • over 10 years ago
    • Processors
    • Processors forum

Didn't find what you are looking for? Post a new question.

  • Ask a new question