ADS8691: how to read register value of bit[0:15]

Hi Ben,

Here is an example to use READ_HWORD command to read the 16-bit of ALARM_H_TH_REG Register:

(Byte 0 Address for bits 7-0 = 24h, Byte 1 Address for bits 15-8 = 25h, Byte 2 Address for bits 23-16 = 26h, Byte 3 Address for bits 31-24 = 27h)

1. Use Read_HWORD command to read the 16-bit (0~15 bit) of register:

             Data frame:         <11001_xx> <0_0010_0100><00000000><00000000>

1. Use Read_HWORD command to read the 16-bit (16~31 bit) of register:

             Data frame:         <11001_xx> <0_0010_0110><00000000><00000000>

Please note:

1. A “0” should be added prior to the address to have a 9-bit address: 0_0010_0100b for address 24h.
2. LSB of the 9-bit address is always ignored and considered as 0b.
3. To write/read both byte 0 and byte 1(or byte 2 and byte 3) in one command, the low byte address (byte 0 or 2) should be used. If the address of byte 1 or 3 is given, the LSB (bit 0) will be ignored, because it is a 16 bit address now.
4. HWORD commands can be only written to the addresses of byte 0+byte 1 or byte 2+byte 3 and so on. They cannot be used for byte 1+ byte 2.

Thanks&regards,

Dale