On page 6 of the documnet "Circuit protection for your next USB Type-C™ design White Paper " says ,when CC Short-to-VBUS through a cable,during the ringing the maxium voltage can be up to 44V ?How do you get 44V?
Below is the detailed description,but I still can't understand that,need your help!!!
As the waveform shows, when a cable is present during a short-to-VBUS event, enough inductance exists in the resistor-inductor-capacitor (RLC) circuit relative to the resistance and capacitance to generate a peak voltage during the ringing that is nearly double the value of the settling or final voltage. If the CC line capacitors de-rate greatly over their voltage range, then the peak voltage that is present during the ringing can be more than double the setting or final voltage. This means for a 22-V short, up to 44 V can be seen on the CC or SBU lines during a short-to-VBUS event. What was initially thought to require only 22-V protection ends up needing to be 44 V.
Thanks~