TXS0102: When one port of the device is pulled low, where is the direction of the current flowing through the input/output internal pull-up resistor?

Hi,

If a master device make the I2C signal low, will the current through the internal pull-up resistors on both the input and output port flow to the master device as shown in the figure below?

In other words, when the Master or the Slave device on the i2c (SDA or SCL) line pulls low, the N2 channel inside the TXS0102 will be closed, and the internal resistors of TXS0102 will be connected in parallel and the resistance will be reduced to 5Kohm. Is it right?

Thanks.