Other Parts Discussed in Thread: TXU0202-Q1
Hi,
This IC is used as a bidirectional UART. In the schematics shown below, The output A port is 1.8V level and output B is 3.3V.
The issue is the B2 voltage level is 1.8V. What is the issue?
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Hi,
This IC is used as a bidirectional UART. In the schematics shown below, The output A port is 1.8V level and output B is 3.3V.
The issue is the B2 voltage level is 1.8V. What is the issue?
The LSF is a passive switch and outputs open-drain signals. You need a pull-up resistor at B2, and a pull-up resistor at A1 would make the signal more robust.
For UART signals, a buffered translator like the TXU0202-Q1 would be a better solution.
Hi,
We removed the pull-up 200K, directly connected to 3.3V. After the change, we got 3.3V in the RX line.
Is any pull-up resistor needed in the VCCB and EN?
If it's directly connected to the buffer anything is happens in the buffer?
Regards,
JIJU RAJ K
The 200 kΩ resistor is needed for the LSF to work correctly. Without it, a high current leaks into the lower supply, and the low-voltage outputs are not clamped to Vref_A.
Pins 2 and 7 are not power supplies but reference voltage inputs. And the LSF is not a buffer. See [FAQ] How do the LSF translators work?
ti.com/quality-reliability-packaging-download/report?opn=TXU0202QDCURQ1 lists the AEC Q100 tests.