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Can we get some input on the expected operation of BQ24230, we are a little confused by the datasheet?
The part is already a consumer device presently in DFM but we are new to the team.
Thanks in advance!
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USE-CASE #1 (TWO BATTERIES)
Vin =4.2V
Vbat = 4.0V
Questions: Will Vin begin to charge Vbat WHILE the Vout is connected to Vbat (i.e. Vout = 4.0V)
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USE-CASE #2 (DEEP DISCHARGE)
Vin = 4.2V
Vbat = 0V (Open circuit protection tripped)
Will the Vbat receive conditioning current charge WHILE Vout is regulated to 4.4V? (provided: total Iin < 500mA)
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USE-CASE #3 (CHARGER PRESENT)
Vin = 5.0V
Vbat = 4.0V (Open circuit protection tripped)
Will the Vbat receive charge and WHILE the Vout is regulated at 4.4V? May the load draw 1.5A total?
Hello Andrew,
Case #1: You don't want to short VBAT and VOUT as this will bypass a lot of the internal circuitry. Out and VBAT are regulated to do different things. You'll pretty much have Constant Voltage on your battery which could damage it.
Case #2: VOUT wont be regulated to 4.4V because VIN is below 4.4V. If the battery was present, you wont charge because VIN is below Vin-DPM ( 4.5V). When the battery is absent, the battery detection routine is run as explained below. IBAT(det) is 7.5mA.
Case #3: VBAT detection will be run and 7.5mA will be used to close the open circuit. If the load draws 1.5A, the battery will supplement with 1A since the maximum input current is 0.5A. This is explained in section 8.3.3.1.3 of the datasheet.
Regards,
Raheem
