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TPS92692: 400W LED Driver Circuit Review Request(TPS92692)

JAEWOONG CHUNG
Prodigy 140 points
Part Number: TPS92692

Hello team. 

We would like to ask for advice again regarding circuit design using TPS92692.

We are going to make an LED driver board that can turn on 400W power LED board.

Please look at the circuit and advise if there is any problem.

For your information, N-MOSFET, P-MOSFET, and Rectifier Diode all use the TO-220 package type and apply a heat dissipation method that attaches the rear of each part to a single aluminum heat sink of 140X20X40mm. And I will blow the heat sink with a fan.

Each part has been randomly selected and may be changed to a variable such as a supply and demand problem in the future, but the main specifications will remain as specified in the circuit diagram as possible.

Thank you.

300W LED Driver circuit(201012).pdf

  • 0
    TI__Mastermind 18890 points

    Hi Jaewoong,

    I've replied to you on this subject before so please see my previous E2E reply here.  In general, the TPS92692 is a controller and the output power depends on the external component and power and heat dissipation and the gate drive capability to the external FET.  You will have about 87% to 90% efficiency so at 400W you will have to get dissipate more than 50W and all this depends on you external components and heat sinking/fan.  I cannot comment on your thermal design here except to tell you approximately the heat you have to get rid off.  You will have to design and test it with the heat sink and fan that you have.

    A few of comments:

    1.  You should use a higher current rating inductor with Saturation current of 26A or more.  This will give some headroom if you need to reduce the switching frequency because of switching loss.  The other reason is input voltage drop due to high current level.

    2.  The RIS (R5) will have greater than 20A going thru with close to 4W so the layout is very critical not only to get heat out but any other impedance of traces will add on.  You also might also want to reduce this to 0.007 or 0.008 Ohm

    3.  I would start out with compensation (C35) being 0.22uF to get the system stable first to test and optimize it later.

    4.  The layout for this is very critical with such high current and power.

    https://e2e.ti.com/support/power-management/f/196/t/905535?tisearch=e2e-sitesearch&keymatch=%2525252520user%252525253A439149

    Thanks Tuan