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Original question:

ALM2402-Q1: Thermal shutdown and safe operating temperature related

ALM2402-Q1: ALM2402 OTF pin specification

Yusuf Korkmaz
Prodigy 50 points
Part Number: ALM2402-Q1
Other Parts Discussed in Thread: ALM2402F-Q1, , ALM2403-Q1

Hello together,

I am currently using the ALM2402F in my resolver application. My question is related to the OTF pin: in the datasheet is specified 5V as max. recommended operation voltage on the OTF pin - and the abs. max. is specified with 7V. In my application in nominal case i pull-up this pin to a 5V source to enable the IC. But when make a tolerance calculation I noticed that the 5V source can go up to 5.7V in worst-case condition.

Do you see any problems by pulling the pin up to 5.7V in a worst-case condition. I have a current limitation resistors (1k) before the pin - but this helps not for the enabling.

Thanks in advance and BR

  • +1
    TI__Guru 50941 points

    Hi Yusuf, 

    I think that you know we have ALM2402-Q1 and ALM2402F-Q1 resolver drivers (also ALM2403-Q1). ALM2402F-Q1 will drive resolver better due to its larger full power bandwidth or higher slew rate. ALM2402F-Q1 is the improved revision of the ALM2402-Q1 IC design. 

    Yusuf Korkmaz said:
    Do you see any problems by pulling the pin up to 5.7V in a worst-case condition. I have a current limitation resistors (1k) before the pin - but this helps not for the enabling.

    Your application will be acceptable, if the pull-up voltage is up to 5.7Vdc in the worst case. The absolute max. rating on the pin is 7Vdc (referenced to GND). I would recommend to change the pull-up resistor to 5-10kΩ, which it will limit the current to ~1mA. 1kΩ pull-up resistor will work also, but it will sink unnecessary extra mAs to the resolver driver. 

    If you have other questions, please let me know. 

    Best,

    Raymond