AMC1211-Q1: AMC1211AQDWVQ1

Part Number: AMC1211-Q1

Tool/software:

i am using AMC1211AQDWVQ1 part as analog isolator and i would like to add protection diode as BAS116 to input pin. do we have any restriction to add protection diode which is pulled up with +5v and one will be added  as pull down with GND 

can you please recommend

  • The BAS116 is not a Schottky diode.

    These are fine. If you want to limit the current through the internal clamping diodes, add a series resistor between the external ones and the pin.

  • Can you please rough connection. about this series resistor how to connect

  • The resistor forces most of the clamping current to flow through the external diode.

  • Thank you for your response. do we have any specific value range for this resister

  • Even a small resistor like 50 Ω would prevent most of the current from flowing into the AMC.

    The AMC has an input bias current of at most 15 nA, so even a large resistor like 10 kΩ would result in an error of 150 µV, which would be much smaller than the AMC's input offset error of 1.5 mV.

    The resistor and the AMC's input capacitance form a low-pass filter, but it will not affect a 220 kHz signal.

    Anything between, say, 100 Ω and 1 kΩ would be fine.

  • dear team,

    can you please suggest analog isolator IC with unity gain and single ended out put,.

    AMC1211AQDWVQ1 in this IC I can see its differential ended output. can you please suggest one single ended IC 

  • Hi Bincy,

    What is your project? 

    I do not believe we have a single ended output device replacement for the AMC1211 at the moment. 

    Alternatively, section 8.2.2.2 of the datasheet details how to convert the differential output to single-ended. 

    Or, if you are not looking to include another stage to your system, you can just use one output. Then, tie the other output to ground through a 10k resistor for best practice. This will only leave you with half the full-scale range and without filtering, however.

    Please let me know if I can answer any more questions. 

    Best regards,

    Eva