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SN65HVDA1050A-Q1: Substitution of SN65HVD251

Daniel Flor
Intellectual 430 points
Part Number: SN65HVDA1050A-Q1
Other Parts Discussed in Thread: SN65HVD251, TCAN1051

Hello,

I'm redesigning my automotive scan tool and I want to use the SN65HVD251 instead of SN65HVDA1050AQDRQ1. The only relevant difference I found between them was the hysteresis of the receiver which for the model SN65HVDA1050AQDRQ1 is 125mV while for the model SN65HVD251 it is 100mV. The two ICs are very similar, but the SN65HVDA1050AQDRQ1 is cheaper.

I know that SN65HVD251 can work with Single Wire CAN, but I don't know the same about SN65HVDA1050AQDRQ1 .

So, What would be the impact of using the SN65HVDA1050AQDRQ1 instead of SN65HVD251 ?

Regards,

Daniel.

  • 0
    TI__Guru 62910 points

    Hello,

    These two are functionally equivalent and could be considered drop-in replacements. There are some minor parametric differences which are documented in the datasheet electrical/switching characteristics tables.

    Have you considered TCAN1051? It is a newer device which maintains pinout compatibility to these two older transceivers. I'd recommend this one over the legacy transceiver products for new designs. It improves a number of things such as voltage tolerance and EMC performance.

    Max

  • 0 in reply to Max Robertson
    Intellectual 430 points

    Yes, I took a look, it seems to be a good replacement for the SN65HVD251.  However, I know that SN65HVD251 can work with Single Wire CAN , there is a Texas's presentation in .ppt, "Single Wire CAN Industrial Interface Applications July 2015" that explain how it can be done. So, I would like to know if this new transceiver, TCAN1051, can do the same.SingleWireCAN.pptx

  • 0 in reply to Daniel Flor
    TI__Guru 62910 points

    Yes, I can confirm that the operation of TCAN1051 will be the same when operated with CANL shorted to ground as in the "SingleWireCAN.pptx" presentation you linked.  In the "dominant" state CANH will be pulled higher than CANL (creating a large enough differential voltage to be detected as a dominant state by a CAN receiver) and in the "recessive" state CANH and CANL will both be near 0 V (resulting in a small enough differential voltage to be detected as a recessive state by a CAN receiver).

    Regards,
    Max